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1/*
2 * Copyright (c) 2010 Broadcom Corporation
3 *
4 * Permission to use, copy, modify, and/or distribute this software for any
5 * purpose with or without fee is hereby granted, provided that the above
6 * copyright notice and this permission notice appear in all copies.
7 *
8 * THE SOFTWARE IS PROVIDED "AS IS" AND THE AUTHOR DISCLAIMS ALL WARRANTIES
9 * WITH REGARD TO THIS SOFTWARE INCLUDING ALL IMPLIED WARRANTIES OF
10 * MERCHANTABILITY AND FITNESS. IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY
11 * SPECIAL, DIRECT, INDIRECT, OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES
12 * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN ACTION
13 * OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF OR IN
14 * CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE.
15 */
16
17#include "qmath.h"
18
19/*
20Description: This function saturate input 32 bit number into a 16 bit number.
21If input number is greater than 0x7fff then output is saturated to 0x7fff.
22else if input number is less than 0xffff8000 then output is saturated to 0xffff8000
23else output is same as input.
24*/
25int16 qm_sat32(int32 op)
26{
27 int16 result;
28 if (op > (int32) 0x7fff) {
29 result = 0x7fff;
30 } else if (op < (int32) 0xffff8000) {
31 result = (int16) (0x8000);
32 } else {
33 result = (int16) op;
34 }
35 return result;
36}
37
38/*
39Description: This function multiply two input 16 bit numbers and return the 32 bit result.
40This multiplication is similar to compiler multiplication. This operation is defined if
4116 bit multiplication on the processor platform is cheaper than 32 bit multiplication (as
42the most of qmath functions can be replaced with processor intrinsic instructions).
43*/
44int32 qm_mul321616(int16 op1, int16 op2)
45{
90ea2296 46 return (int32) (op1) * (int32) (op2);
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47}
48
49/*
50Description: This function make 16 bit multiplication and return the result in 16 bits.
51To fit the result into 16 bits the 32 bit multiplication result is right
52shifted by 16 bits.
53*/
54int16 qm_mul16(int16 op1, int16 op2)
55{
56 int32 result;
57 result = ((int32) (op1) * (int32) (op2));
90ea2296 58 return (int16) (result >> 16);
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59}
60
61/*
62Description: This function multiply two 16 bit numbers and return the result in 32 bits.
63This function remove the extra sign bit created by the multiplication by leftshifting the
6432 bit multiplication result by 1 bit before returning the result. So the output is
65twice that of compiler multiplication. (i.e. qm_muls321616(2,3)=12).
66When both input 16 bit numbers are 0x8000, then the result is saturated to 0x7fffffff.
67*/
68int32 qm_muls321616(int16 op1, int16 op2)
69{
70 int32 result;
71 if (op1 == (int16) (0x8000) && op2 == (int16) (0x8000)) {
72 result = 0x7fffffff;
73 } else {
74 result = ((int32) (op1) * (int32) (op2));
75 result = result << 1;
76 }
77 return result;
78}
79
80/*
81Description: This function make 16 bit unsigned multiplication. To fit the output into
8216 bits the 32 bit multiplication result is right shifted by 16 bits.
83*/
7d4df48e 84u16 qm_mulu16(u16 op1, u16 op2)
a9533e7e 85{
7d4df48e 86 return (u16) (((uint32) op1 * (uint32) op2) >> 16);
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87}
88
89/*
90Description: This function make 16 bit multiplication and return the result in 16 bits.
91To fit the multiplication result into 16 bits the multiplication result is right shifted by
9215 bits. Right shifting 15 bits instead of 16 bits is done to remove the extra sign bit formed
93due to the multiplication.
94When both the 16bit inputs are 0x8000 then the output is saturated to 0x7fffffff.
95*/
96int16 qm_muls16(int16 op1, int16 op2)
97{
98 int32 result;
99 if (op1 == (int16) 0x8000 && op2 == (int16) 0x8000) {
100 result = 0x7fffffff;
101 } else {
102 result = ((int32) (op1) * (int32) (op2));
103 }
90ea2296 104 return (int16) (result >> 15);
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105}
106
107/*
108Description: This function add two 32 bit numbers and return the 32bit result.
109If the result overflow 32 bits, the output will be saturated to 32bits.
110*/
111int32 qm_add32(int32 op1, int32 op2)
112{
113 int32 result;
114 result = op1 + op2;
115 if (op1 < 0 && op2 < 0 && result > 0) {
116 result = 0x80000000;
117 } else if (op1 > 0 && op2 > 0 && result < 0) {
118 result = 0x7fffffff;
119 }
120 return result;
121}
122
123/*
124Description: This function add two 16 bit numbers and return the 16bit result.
125If the result overflow 16 bits, the output will be saturated to 16bits.
126*/
127int16 qm_add16(int16 op1, int16 op2)
128{
129 int16 result;
130 int32 temp = (int32) op1 + (int32) op2;
131 if (temp > (int32) 0x7fff) {
132 result = (int16) 0x7fff;
133 } else if (temp < (int32) 0xffff8000) {
134 result = (int16) 0xffff8000;
135 } else {
136 result = (int16) temp;
137 }
138 return result;
139}
140
141/*
142Description: This function make 16 bit subtraction and return the 16bit result.
143If the result overflow 16 bits, the output will be saturated to 16bits.
144*/
145int16 qm_sub16(int16 op1, int16 op2)
146{
147 int16 result;
148 int32 temp = (int32) op1 - (int32) op2;
149 if (temp > (int32) 0x7fff) {
150 result = (int16) 0x7fff;
151 } else if (temp < (int32) 0xffff8000) {
152 result = (int16) 0xffff8000;
153 } else {
154 result = (int16) temp;
155 }
156 return result;
157}
158
159/*
160Description: This function make 32 bit subtraction and return the 32bit result.
161If the result overflow 32 bits, the output will be saturated to 32bits.
162*/
163int32 qm_sub32(int32 op1, int32 op2)
164{
165 int32 result;
166 result = op1 - op2;
167 if (op1 >= 0 && op2 < 0 && result < 0) {
168 result = 0x7fffffff;
169 } else if (op1 < 0 && op2 > 0 && result > 0) {
170 result = 0x80000000;
171 }
172 return result;
173}
174
175/*
176Description: This function multiply input 16 bit numbers and accumulate the result
177into the input 32 bit number and return the 32 bit accumulated result.
178If the accumulation result in overflow, then the output will be saturated.
179*/
180int32 qm_mac321616(int32 acc, int16 op1, int16 op2)
181{
182 int32 result;
183 result = qm_add32(acc, qm_mul321616(op1, op2));
184 return result;
185}
186
187/*
188Description: This function make a 32 bit saturated left shift when the specified shift
189is +ve. This function will make a 32 bit right shift when the specified shift is -ve.
190This function return the result after shifting operation.
191*/
192int32 qm_shl32(int32 op, int shift)
193{
194 int i;
195 int32 result;
196 result = op;
197 if (shift > 31)
198 shift = 31;
199 else if (shift < -31)
200 shift = -31;
201 if (shift >= 0) {
202 for (i = 0; i < shift; i++) {
203 result = qm_add32(result, result);
204 }
205 } else {
206 result = result >> (-shift);
207 }
208 return result;
209}
210
211/*
212Description: This function make a 32 bit right shift when shift is +ve.
213This function make a 32 bit saturated left shift when shift is -ve. This function
214return the result of the shift operation.
215*/
216int32 qm_shr32(int32 op, int shift)
217{
218 return qm_shl32(op, -shift);
219}
220
221/*
222Description: This function make a 16 bit saturated left shift when the specified shift
223is +ve. This function will make a 16 bit right shift when the specified shift is -ve.
224This function return the result after shifting operation.
225*/
226int16 qm_shl16(int16 op, int shift)
227{
228 int i;
229 int16 result;
230 result = op;
231 if (shift > 15)
232 shift = 15;
233 else if (shift < -15)
234 shift = -15;
235 if (shift > 0) {
236 for (i = 0; i < shift; i++) {
237 result = qm_add16(result, result);
238 }
239 } else {
240 result = result >> (-shift);
241 }
242 return result;
243}
244
245/*
246Description: This function make a 16 bit right shift when shift is +ve.
247This function make a 16 bit saturated left shift when shift is -ve. This function
248return the result of the shift operation.
249*/
250int16 qm_shr16(int16 op, int shift)
251{
252 return qm_shl16(op, -shift);
253}
254
255/*
256Description: This function return the number of redundant sign bits in a 16 bit number.
257Example: qm_norm16(0x0080) = 7.
258*/
259int16 qm_norm16(int16 op)
260{
7d4df48e 261 u16 u16extraSignBits;
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262 if (op == 0) {
263 return 15;
264 } else {
265 u16extraSignBits = 0;
266 while ((op >> 15) == (op >> 14)) {
267 u16extraSignBits++;
268 op = op << 1;
269 }
270 }
271 return u16extraSignBits;
272}
273
274/*
275Description: This function return the number of redundant sign bits in a 32 bit number.
276Example: qm_norm32(0x00000080) = 23
277*/
278int16 qm_norm32(int32 op)
279{
7d4df48e 280 u16 u16extraSignBits;
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281 if (op == 0) {
282 return 31;
283 } else {
284 u16extraSignBits = 0;
285 while ((op >> 31) == (op >> 30)) {
286 u16extraSignBits++;
287 op = op << 1;
288 }
289 }
290 return u16extraSignBits;
291}
292
293/*
294Description: This function divide two 16 bit unsigned numbers.
295The numerator should be less than denominator. So the quotient is always less than 1.
296This function return the quotient in q.15 format.
297*/
298int16 qm_div_s(int16 num, int16 denom)
299{
300 int16 var_out;
301 int16 iteration;
302 int32 L_num;
303 int32 L_denom;
304 L_num = (num) << 15;
305 L_denom = (denom) << 15;
306 for (iteration = 0; iteration < 15; iteration++) {
307 L_num <<= 1;
308 if (L_num >= L_denom) {
309 L_num = qm_sub32(L_num, L_denom);
310 L_num = qm_add32(L_num, 1);
311 }
312 }
313 var_out = (int16) (L_num & 0x7fff);
90ea2296 314 return var_out;
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315}
316
317/*
318Description: This function compute the absolute value of a 16 bit number.
319*/
320int16 qm_abs16(int16 op)
321{
322 if (op < 0) {
323 if (op == (int16) 0xffff8000) {
324 return 0x7fff;
325 } else {
326 return -op;
327 }
328 } else {
329 return op;
330 }
331}
332
333/*
334Description: This function divide two 16 bit numbers.
335The quotient is returned through return value.
336The qformat of the quotient is returned through the pointer (qQuotient) passed
337to this function. The qformat of quotient is adjusted appropriately such that
338the quotient occupies all 16 bits.
339*/
7cc4a4c0 340int16 qm_div16(int16 num, int16 denom, int16 *qQuotient)
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341{
342 int16 sign;
343 int16 nNum, nDenom;
344 sign = num ^ denom;
345 num = qm_abs16(num);
346 denom = qm_abs16(denom);
347 nNum = qm_norm16(num);
348 nDenom = qm_norm16(denom);
349 num = qm_shl16(num, nNum - 1);
350 denom = qm_shl16(denom, nDenom);
351 *qQuotient = nNum - 1 - nDenom + 15;
352 if (sign >= 0) {
353 return qm_div_s(num, denom);
354 } else {
355 return -qm_div_s(num, denom);
356 }
357}
358
359/*
360Description: This function compute absolute value of a 32 bit number.
361*/
362int32 qm_abs32(int32 op)
363{
364 if (op < 0) {
365 if (op == (int32) 0x80000000) {
366 return 0x7fffffff;
367 } else {
368 return -op;
369 }
370 } else {
371 return op;
372 }
373}
374
375/*
376Description: This function divide two 32 bit numbers. The division is performed
377by considering only important 16 bits in 32 bit numbers.
378The quotient is returned through return value.
379The qformat of the quotient is returned through the pointer (qquotient) passed
380to this function. The qformat of quotient is adjusted appropriately such that
381the quotient occupies all 16 bits.
382*/
7cc4a4c0 383int16 qm_div163232(int32 num, int32 denom, int16 *qquotient)
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384{
385 int32 sign;
386 int16 nNum, nDenom;
387 sign = num ^ denom;
388 num = qm_abs32(num);
389 denom = qm_abs32(denom);
390 nNum = qm_norm32(num);
391 nDenom = qm_norm32(denom);
392 num = qm_shl32(num, nNum - 1);
393 denom = qm_shl32(denom, nDenom);
394 *qquotient = nNum - 1 - nDenom + 15;
395 if (sign >= 0) {
396 return qm_div_s((int16) (num >> 16), (int16) (denom >> 16));
397 } else {
398 return -qm_div_s((int16) (num >> 16), (int16) (denom >> 16));
399 }
400}
401
402/*
403Description: This function multiply a 32 bit number with a 16 bit number.
404The multiplicaton result is right shifted by 16 bits to fit the result
405into 32 bit output.
406*/
407int32 qm_mul323216(int32 op1, int16 op2)
408{
409 int16 hi;
7d4df48e 410 u16 lo;
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411 int32 result;
412 hi = op1 >> 16;
413 lo = (int16) (op1 & 0xffff);
414 result = qm_mul321616(hi, op2);
415 result = result + (qm_mulsu321616(op2, lo) >> 16);
416 return result;
417}
418
419/*
420Description: This function multiply signed 16 bit number with unsigned 16 bit number and return
421the result in 32 bits.
422*/
7d4df48e 423int32 qm_mulsu321616(int16 op1, u16 op2)
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424{
425 return (int32) (op1) * op2;
426}
427
428/*
429Description: This function multiply 32 bit number with 16 bit number. The multiplication result is
430right shifted by 15 bits to fit the result into 32 bits. Right shifting by only 15 bits instead of
43116 bits is done to remove the extra sign bit formed by multiplication from the return value.
432When the input numbers are 0x80000000, 0x8000 the return value is saturated to 0x7fffffff.
433*/
434int32 qm_muls323216(int32 op1, int16 op2)
435{
436 int16 hi;
7d4df48e 437 u16 lo;
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438 int32 result;
439 hi = op1 >> 16;
440 lo = (int16) (op1 & 0xffff);
441 result = qm_muls321616(hi, op2);
442 result = qm_add32(result, (qm_mulsu321616(op2, lo) >> 15));
443 return result;
444}
445
446/*
447Description: This function multiply two 32 bit numbers. The multiplication result is right
448shifted by 32 bits to fit the multiplication result into 32 bits. The right shifted
449multiplication result is returned as output.
450*/
451int32 qm_mul32(int32 a, int32 b)
452{
453 int16 hi1, hi2;
7d4df48e 454 u16 lo1, lo2;
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455 int32 result;
456 hi1 = a >> 16;
457 hi2 = b >> 16;
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458 lo1 = (u16) (a & 0xffff);
459 lo2 = (u16) (b & 0xffff);
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460 result = qm_mul321616(hi1, hi2);
461 result = result + (qm_mulsu321616(hi1, lo2) >> 16);
462 result = result + (qm_mulsu321616(hi2, lo1) >> 16);
463 return result;
464}
465
466/*
467Description: This function multiply two 32 bit numbers. The multiplication result is
468right shifted by 31 bits to fit the multiplication result into 32 bits. The right
469shifted multiplication result is returned as output. Right shifting by only 31 bits
470instead of 32 bits is done to remove the extra sign bit formed by multiplication.
471When the input numbers are 0x80000000, 0x80000000 the return value is saturated to
4720x7fffffff.
473*/
474int32 qm_muls32(int32 a, int32 b)
475{
476 int16 hi1, hi2;
7d4df48e 477 u16 lo1, lo2;
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478 int32 result;
479 hi1 = a >> 16;
480 hi2 = b >> 16;
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481 lo1 = (u16) (a & 0xffff);
482 lo2 = (u16) (b & 0xffff);
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483 result = qm_muls321616(hi1, hi2);
484 result = qm_add32(result, (qm_mulsu321616(hi1, lo2) >> 15));
485 result = qm_add32(result, (qm_mulsu321616(hi2, lo1) >> 15));
486 result = qm_add32(result, (qm_mulu16(lo1, lo2) >> 15));
487 return result;
488}
489
490/* This table is log2(1+(i/32)) where i=[0:1:31], in q.15 format */
491static const int16 log_table[] = {
492 0,
493 1455,
494 2866,
495 4236,
496 5568,
497 6863,
498 8124,
499 9352,
500 10549,
501 11716,
502 12855,
503 13968,
504 15055,
505 16117,
506 17156,
507 18173,
508 19168,
509 20143,
510 21098,
511 22034,
512 22952,
513 23852,
514 24736,
515 25604,
516 26455,
517 27292,
518 28114,
519 28922,
520 29717,
521 30498,
522 31267,
523 32024
524};
525
526#define LOG_TABLE_SIZE 32 /* log_table size */
527#define LOG2_LOG_TABLE_SIZE 5 /* log2(log_table size) */
528#define Q_LOG_TABLE 15 /* qformat of log_table */
529#define LOG10_2 19728 /* log10(2) in q.16 */
530
531/*
532Description:
533This routine takes the input number N and its q format qN and compute
534the log10(N). This routine first normalizes the input no N. Then N is in mag*(2^x) format.
535mag is any number in the range 2^30-(2^31 - 1). Then log2(mag * 2^x) = log2(mag) + x is computed.
536From that log10(mag * 2^x) = log2(mag * 2^x) * log10(2) is computed.
537This routine looks the log2 value in the table considering LOG2_LOG_TABLE_SIZE+1 MSBs.
538As the MSB is always 1, only next LOG2_OF_LOG_TABLE_SIZE MSBs are used for table lookup.
539Next 16 MSBs are used for interpolation.
540Inputs:
541N - number to which log10 has to be found.
542qN - q format of N
543log10N - address where log10(N) will be written.
544qLog10N - address where log10N qformat will be written.
545Note/Problem:
546For accurate results input should be in normalized or near normalized form.
547*/
7cc4a4c0 548void qm_log10(int32 N, int16 qN, int16 *log10N, int16 *qLog10N)
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549{
550 int16 s16norm, s16tableIndex, s16errorApproximation;
7d4df48e 551 u16 u16offset;
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552 int32 s32log;
553
554 /* Logerithm of negative values is undefined.
555 * assert N is greater than 0.
556 */
557 /* ASSERT(N > 0); */
558
559 /* normalize the N. */
560 s16norm = qm_norm32(N);
561 N = N << s16norm;
562
563 /* The qformat of N after normalization.
564 * -30 is added to treat the no as between 1.0 to 2.0
565 * i.e. after adding the -30 to the qformat the decimal point will be
566 * just rigtht of the MSB. (i.e. after sign bit and 1st MSB). i.e.
567 * at the right side of 30th bit.
568 */
569 qN = qN + s16norm - 30;
570
571 /* take the table index as the LOG2_OF_LOG_TABLE_SIZE bits right of the MSB */
572 s16tableIndex = (int16) (N >> (32 - (2 + LOG2_LOG_TABLE_SIZE)));
573
574 /* remove the MSB. the MSB is always 1 after normalization. */
575 s16tableIndex =
576 s16tableIndex & (int16) ((1 << LOG2_LOG_TABLE_SIZE) - 1);
577
578 /* remove the (1+LOG2_OF_LOG_TABLE_SIZE) MSBs in the N. */
579 N = N & ((1 << (32 - (2 + LOG2_LOG_TABLE_SIZE))) - 1);
580
581 /* take the offset as the 16 MSBS after table index.
582 */
7d4df48e 583 u16offset = (u16) (N >> (32 - (2 + LOG2_LOG_TABLE_SIZE + 16)));
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584
585 /* look the log value in the table. */
586 s32log = log_table[s16tableIndex]; /* q.15 format */
587
588 /* interpolate using the offset. */
7d4df48e 589 s16errorApproximation = (int16) qm_mulu16(u16offset, (u16) (log_table[s16tableIndex + 1] - log_table[s16tableIndex])); /* q.15 */
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590
591 s32log = qm_add16((int16) s32log, s16errorApproximation); /* q.15 format */
592
593 /* adjust for the qformat of the N as
594 * log2(mag * 2^x) = log2(mag) + x
595 */
29c4275a 596 s32log = qm_add32(s32log, ((int32) -qN) << 15); /* q.15 format */
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597
598 /* normalize the result. */
599 s16norm = qm_norm32(s32log);
600
601 /* bring all the important bits into lower 16 bits */
602 s32log = qm_shl32(s32log, s16norm - 16); /* q.15+s16norm-16 format */
603
604 /* compute the log10(N) by multiplying log2(N) with log10(2).
605 * as log10(mag * 2^x) = log2(mag * 2^x) * log10(2)
606 * log10N in q.15+s16norm-16+1 (LOG10_2 is in q.16)
607 */
608 *log10N = qm_muls16((int16) s32log, (int16) LOG10_2);
609
610 /* write the q format of the result. */
611 *qLog10N = 15 + s16norm - 16 + 1;
612
613 return;
614}
615
616/*
617Description:
618This routine compute 1/N.
619This routine reformates the given no N as N * 2^qN where N is in between 0.5 and 1.0
620in q.15 format in 16 bits. So the problem now boils down to finding the inverse of a
621q.15 no in 16 bits which is in the range of 0.5 to 1.0. The output is always between
6222.0 to 1. So the output is 2.0 to 1.0 in q.30 format. Once the final output format is found
623by taking the qN into account. Inverse is found with newton rapson method. Initially
624inverse (x) is guessed as 1/0.75 (with appropriate sign). The new guess is calculated
625using the formula x' = 2*x - N*x*x. After 4 or 5 iterations the inverse is very close to
626inverse of N.
627Inputs:
628N - number to which 1/N has to be found.
629qn - q format of N.
630sqrtN - address where 1/N has to be written.
631qsqrtN - address where q format of 1/N has to be written.
632*/
633#define qx 29
7cc4a4c0 634void qm_1byN(int32 N, int16 qN, int32 *result, int16 *qResult)
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635{
636 int16 normN;
637 int32 s32firstTerm, s32secondTerm, x;
638 int i;
639
640 normN = qm_norm32(N);
641
642 /* limit N to least significant 16 bits. 15th bit is the sign bit. */
643 N = qm_shl32(N, normN - 16);
644 qN = qN + normN - 16 - 15;
645 /* -15 is added to treat N as 16 bit q.15 number in the range from 0.5 to 1 */
646
647 /* Take the initial guess as 1/0.75 in qx format with appropriate sign. */
648 if (N >= 0) {
649 x = (int32) ((1 / 0.75) * (1 << qx));
650 /* input no is in the range 0.5 to 1. So 1/0.75 is taken as initial guess. */
651 } else {
652 x = (int32) ((1 / -0.75) * (1 << qx));
653 /* input no is in the range -0.5 to -1. So 1/-0.75 is taken as initial guess. */
654 }
655
656 /* iterate the equation x = 2*x - N*x*x for 4 times. */
657 for (i = 0; i < 4; i++) {
658 s32firstTerm = qm_shl32(x, 1); /* s32firstTerm = 2*x in q.29 */
659 s32secondTerm =
660 qm_muls321616((int16) (s32firstTerm >> 16),
661 (int16) (s32firstTerm >> 16));
662 /* s32secondTerm = x*x in q.(29+1-16)*2+1 */
663 s32secondTerm =
664 qm_muls321616((int16) (s32secondTerm >> 16), (int16) N);
665 /* s32secondTerm = N*x*x in q.((29+1-16)*2+1)-16+15+1 i.e. in q.29 */
666 x = qm_sub32(s32firstTerm, s32secondTerm);
667 /* can be added directly as both are in q.29 */
668 }
669
670 /* Bring the x to q.30 format. */
671 *result = qm_shl32(x, 1);
672 /* giving the output in q.30 format for q.15 input in 16 bits. */
673
674 /* compute the final q format of the result. */
675 *qResult = -qN + 30; /* adjusting the q format of actual output */
676
677 return;
678}
679
680#undef qx