Problem A |
Bit Mask |
Time Limit |
1 Second |
In bit-wise expression, mask is a common term. You can get a certain bit-pattern using mask. For example, if you want to make first 4 bits of a 32-bit number zero, you can use 0xFFFFFFF0 as mask and perform a bit-wise AND operation. Here you have to find such a bit-mask.
Consider you are given a 32-bit unsigned integer N. You have to find a mask M such that L ≤ M ≤ U and N OR M is maximum. For example, if N is 100 and L = 50, U = 60 then M will be 59 and N OR M will be 127 which is maximum. If several value of M satisfies the same criteria then you have to print the minimum value of M.
Input
Each input starts with 3 unsigned integers N, L, U where L ≤ U. Input is terminated by EOF.
Output
For each input, print in a line the minimum value of M, which makes N OR M maximum.
Look, a brute force solution may not end within the time limit.
Sample Input |
Output for Sample Input |
100 50 60 |
59 |